WebAug 16, 2015 · Find tan( 7π 12) Ans: - (2 + sqrt3) Explanation: Call tan( 7π 12) = t tan2t = tan( 14π 12) = tan( 2π 12 +π) = tan( π 6 + π) = tan( π 6) = 1 √3 Apply the trig identity: tan2t = 2tant 1 − tan2t tan2t = 1 √3 = 2 t 1 − tan2t 1 − t2 = 2√3t --> t2 +2√3t − 1 = 0 D = d2 = b2 − 4ac = 12 +4 = 16 − -> d = ± 4 t = − 2 √3 2 ± 4 2 --> t = tan( 7π 12) = −√3 ± 2 WebJul 12, 2024 · In this video, we will learn to find the value of tan (7pi/12). The Link of the video explaining the proof of the trigonometry Show more Limit of x/ (sqrt (x + 1) - 1) as x approaches 0 Ravi...
How do I find the value of tan(7pi/12)? Socratic
WebRather than think of the circles as having 360 degrees, it has 2π radians. That means π is 180 degrees, and π/2 is 90 degrees. Now 7/12 is just a bit more than 6/12, and 6/12=1/2, right? So 7π/12 is just a wee bit more than 6π/12, which is π/2 which is 90 degrees - so 7π/12 is just a wee bit more than 90 degrees. WebMay 21, 2016 · tan( 7π 12) = −(2 +√3) Explanation: tan( 7π 12) = tan(π− 5π 12) = #-tan ( (5pi)/12) = −tan( 3π 12 + 2π 12) = −tan( π 4 + π 6) Now using tan(A +B) = tanA+ tanB 1 … don\u0027t judge me lyrics kierra sheard
Solved Find the exact values of the sine, cosine, and - Chegg
WebSolve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. WebJul 27, 2016 · sin(7 π 12) = sin( π 4 + π 3) Use the formula sin(a +b) = sinacosb +cosasinb sin( π 4 + π 3) = sin( π 4)cos( π 3) + cos( π 4)sin( π 3)..... > 1 sin( π 4) = √2 2; cos( π 4) = √2 2 sin( π 3) = √3 2; cos( π 3) = 1 2 Plug these values on equation 1 sin( π 4 + π 3) = ( √2 2)( 1 2) + ( √2 2) ⋅ ( √3 2) sin( π 4 + π 3) = √2 +√6 4 Answer link WebThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Find an exact value for tan (7pi/12). Note that 7pi/12 = pi/3 + pi/4 . Find an exact value for tan (7pi/12). Note that 7pi/12 = pi/3 + pi/4 . city of hazard water department